1820 - 1888 (67 years)
| Birth |
18 Dec 1820 |
Bathurst, Eastern Cape, South Africa |
| Died |
9 Aug 1888 |
Jacobsdal, Free State, South Africa |
| |
| Father |
William Streak, 1820 Settler, b. 18 Jun 1791, Wargrave, Berkshire, England |
| Mother |
Elizabeth Louisa Cutler, 1820 Settler, b. 20 Sep 1797, Binfield, Berkshire, England |
| |
| Family |
Louisa Smith, b. Est 1829 |
| Children |
| + | 1. James Neville Streak, b. 1842, Grahamstown, Eastern Cape, South Africa |
| | 2. William George Streak |
| + | 3. Elizabeth Ann Streak, b. Abt 1848 |
| | 4. Robert Cutler Streak |
| + | 5. Louisa Georgina Streak |
| | 6. Eliza Susannah Streak |
| + | 7. Samuel Clifton Streak |
| + | 8. Milton Alfred Streak, b. 5 Oct 1865 |
| + | 9. Jessie Harriet Streak |
| + | 10. Edward Charles Streak |
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| |
Est 1829 -
| Birth |
Est 1829 |
| |
| Family |
William Samuel Streak, b. 18 Dec 1820, Bathurst, Eastern Cape, South Africa |
| Children |
| + | 1. James Neville Streak, b. 1842, Grahamstown, Eastern Cape, South Africa |
| | 2. William George Streak |
| + | 3. Elizabeth Ann Streak, b. Abt 1848 |
| | 4. Robert Cutler Streak |
| + | 5. Louisa Georgina Streak |
| | 6. Eliza Susannah Streak |
| + | 7. Samuel Clifton Streak |
| + | 8. Milton Alfred Streak, b. 5 Oct 1865 |
| + | 9. Jessie Harriet Streak |
| + | 10. Edward Charles Streak |
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| |

| |
| Family |
Jessie Harriet Streak |
| Children |
| | 1. Florrie Pavey |
| | 2. Adeline Pavey |
| | 3. Maud Pavey |
| | 4. Jessie Pavey |
| | 5. Clement C B Pavey |
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| |

| |
| Father |
Pavey |
| Mother |
Jessie Harriet Streak |
| |

| |
| Father |
Pavey |
| Mother |
Jessie Harriet Streak |
| |

| |
| Father |
Pavey |
| Mother |
Jessie Harriet Streak |
| |

| |
| Father |
Pavey |
| Mother |
Jessie Harriet Streak |
| |

| |
| Father |
Pavey |
| Mother |
Jessie Harriet Streak |
| |
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| Name |
Jessie Harriet Streak [1, 2] |
| Gender |
Female |
| 1820 Lineage |
Yes |
| Person ID |
I135662 |
master |
| Last Modified |
7 Dec 2021 |
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Please help towards my time and effort in maintaining this website. Every £, $, € and Rand helps!
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| Many Thanks, Paul
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